Ngo\u00e0i h\u00ecnh th\u1ee9c \u0111\u00e1nh l\u00f4 \u0111\u1ec1 truy\u1ec1n th\u1ed1ng anh em hay ch\u01a1i, c\u00f2n c\u00f3 1 th\u1ec3 lo\u1ea1i kh\u00e1c \u0111\u00f3 l\u00e0 l\u00f4 xi\u00ean, s\u1ebd c\u00f3 nhi\u1ec1u ng\u01b0\u1eddi ch\u01b0a bi\u1ebft \u0111\u1ebfn h\u00ecnh th\u1ee9c nh\u01b0 th\u1ebf n\u00e0y. Ho\u1eb7c t\u00ecm hi\u1ec3u c\u00e1ch ch\u01a1i l\u00f4 xi\u00ean ch\u1eafc \u0103n nh\u1ea5t. H\u00e3y c\u00f9ng t\u00ecm hi\u1ec3u v\u1ec1 l\u00f4 xi\u00ean v\u00e0 b\u00ed k\u00edp \u0103n ti\u1ec1n g\u1ea5p b\u1ed9i nh\u00e9<\/span><\/p>\n L\u00f4 xi\u00ean b\u1ea3n ch\u1ea5t c\u0169ng l\u00e0 s\u1ed1 l\u00f4 \u0111\u1ec1 b\u00ecnh th\u01b0\u1eddng nh\u01b0 ch\u00fang ta \u0111\u00e1nh l\u00f4 : L\u1ea5y 2 ch\u1eef s\u1ed1 cu\u1ed1i c\u1ee7a c\u00e1c gi\u1ea3i (k\u1ec3 c\u1ea3 gi\u1ea3i \u0111\u1eb7c bi\u00eat)<\/span><\/p>\n X\u1ed5 s\u1ed1 Mi\u1ec1n B\u1eafc hi\u1ec7n nay c\u00f3 27 gi\u1ea3i l\u00f4\u00a0<\/span><\/p>\n X\u1ed5 s\u1ed1 mi\u1ec1n Trung, mi\u1ec1n Nam c\u00f3 18 gi\u1ea3i l\u00f4<\/span><\/p>\n L\u00f4 xi\u00ean<\/strong>, hay l\u00e0\u00a0l\u00f4 x\u00e2u<\/strong>\u00a0l\u00e0 m\u1ed9t xi\u00ean ho\u1eb7c m\u1ed9t x\u00e2u k\u1ebft h\u1ee3p t\u1eeb 2, 3 ho\u1eb7c 4 s\u1ed1 l\u00f4. B\u1ea1n \u0111\u00e1nh s\u1ed1 l\u00f4 xi\u00ean 2, ngh\u0129a l\u00e0 b\u1ea1n c\u01b0\u1ee3c c\u00f9ng m\u1ed9t l\u00fac k\u1ebft qu\u1ea3 s\u1ebd xu\u1ea5t hi\u1ec7n c\u1ea3 2 s\u1ed1 b\u1ea1n c\u01b0\u1ee3c.<\/span><\/p>\n V\u1edbi t\u1ef7 l\u1ec7 l\u00f4 xi\u00ean 2 l\u00e0 1 \u0103n 10<\/strong> th\u00ec n\u1ebfu b\u1ea1n \u0111\u00e1nh 100.000 \u0111\u1ed3ng b\u1ea1n s\u1ebd nh\u1eadn \u0111\u01b0\u1ee3c 100.000 x 10 = 1000.000 \u0111\u1ed3ng.<\/span><\/p>\n V\u1edbi t\u1ef7 l\u1ec7 l\u00f4 xi\u00ean 3 l\u00e0 1 \u0103n 40<\/strong> th\u00ec n\u1ebfu b\u1ea1n \u0111\u00e1nh 50.000 \u0111\u1ed3ng b\u1ea1n s\u1ebd nh\u1eadn \u0111\u01b0\u1ee3c 50.000 x 40 = 2.000.000 \u0111\u1ed3ng.<\/span><\/p>\n V\u1edbi t\u1ef7 l\u1ec7 l\u00f4 xi\u00ean 4 l\u00e0 1 \u0103n 100<\/strong> th\u00ec n\u1ebfu b\u1ea1n \u0111\u00e1nh 150.000 \u0111\u1ed3ng b\u1ea1n s\u1ebd nh\u1eadn \u0111\u01b0\u1ee3c 150.000 x 100 = 15.000.000 \u0111\u1ed3ng.<\/span><\/p>\n K\u1ebft qu\u1ea3 l\u00f4 l\u00e0 nh\u1eefng con s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a 27 gi\u1ea3i th\u01b0\u1edfng x\u1ed5 s\u1ed1 ki\u1ebfn thi\u1ebft. V\u1eady trong t\u1ed5ng s\u1ed1 100 s\u1ed1 t\u1eeb 00 \u0111\u1ebfn 99 th\u00ec c\u00f3 27 s\u1ed1 tr\u00f9ng v\u1edbi k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 ki\u1ebfn thi\u1ebft mi\u1ec1n B\u1eafc. V\u1eady x\u00e1c su\u1ea5t tr\u00fang l\u00f4 s\u1ebd l\u00e0 27%.<\/span><\/p>\n N\u1ebfu tr\u01b0\u1eddng h\u1ee3p gi\u1ea3i th\u01b0\u1edfng x\u1ed5 s\u1ed1 kh\u00e1c nhau m\u00e0 s\u1ed1 cu\u1ed1i tr\u00f9ng nhau th\u00ec x\u00e1c su\u1ea5t tr\u00fang l\u00f4 ch\u1ec9 c\u00f2n l\u00e0 23,76%.<\/span><\/p>\n T\u1eeb x\u00e1c su\u1ea5t tr\u00fang l\u00f4 s\u1ebd t\u00ednh ra \u0111\u01b0\u1ee3c x\u00e1c su\u1ea5t th\u1eafng l\u00f4 xi\u00ean nh\u01b0 sau:<\/span><\/p>\n M\u1eb7c d\u00f9 x\u00e1c su\u1ea5t th\u1eafng l\u1edbn nh\u01b0ng ng\u01b0\u1eddi ch\u01a1i v\u1eabn ch\u1ecdn l\u00f4 xi\u00ean 4 \u0111\u1ec3 ch\u01a1i, v\u00ec sao v\u1eady? \u0110\u01a1n gi\u1ea3n v\u00ec x\u00e1c su\u1ea5t th\u1eafng c\u00e0ng th\u1ea5p th\u00ec t\u1ef7 l\u1ec7 tr\u1ea3 th\u01b0\u1edfng c\u00e0ng cao. \u0110\u1ec3 ghi con s\u1ed1 n\u00e0o th\u1eafng con s\u1ed1 \u0111\u00f3 b\u1ea1n c\u00f3 th\u1ec3 tham kh\u1ea3o nh\u1eefng quy lu\u1eadt con s\u1ed1 l\u00f4 hay ra nh\u01b0 sau<\/span><\/p>\n C\u00e1c con l\u00f4 hay ra h\u00e0ng ng\u00e0y: 373, 565, 75, 79, 92<\/span><\/p>\n C\u00e1c con l\u00f4 hay \u0111i k\u00e8m v\u1edbi nhau: 373 \u2013 010, 25\/52 \u2013 22, 76 \u2013 47, 11 \u2013 44, 66 \u2013 33.<\/span><\/p>\n L\u00f4 ra c\u1ea3 c\u1eb7p 060 th\u00ec h\u00f4m sau s\u1ebd c\u00f3 1 con l\u1ea1i v\u1ec1<\/span><\/p>\n L\u00f4 ra 51 th\u00ec h\u00f4m sau s\u1ebd ra con 15<\/span><\/p>\n L\u00f4 ra c\u1ea3 c\u1eb7p 050 ho\u1eb7c h\u00f4m tr\u01b0\u1edbc c\u00f3 1 con \u0111\u00f3 v\u1ec1 th\u00ec h\u00f4m sau s\u1ebd tr\u1ea3 l\u1ea1i 1 con<\/span><\/p>\n L\u00f4 ra c\u1ea3 c\u1eb7p 020 ho\u1eb7c h\u00f4m tr\u01b0\u1edbc c\u00f3 1 con \u0111\u00f3 v\u1ec1 th\u00ec h\u00f4m sau s\u1ebd c\u00f3 con 99, ng\u01b0\u1ee3c l\u1ea1i.<\/span><\/p>\n H\u00f4m tr\u01b0\u1edbc c\u00f3 con l\u00f4 75 th\u00ec h\u00f4m sau s\u1ebd c\u00f3 con l\u00f4 57<\/span><\/p>\n L\u00f4 \u0111\u1ea7u 7 ho\u1eb7c l\u00f4 \u0111\u00edt 3 c\u00e2m th\u00ec h\u00f4m sau s\u1ebd c\u00f3 con l\u00f4 73<\/span><\/p>\n H\u00f4m tr\u01b0\u1edbc c\u00f3 con l\u00f4 97 th\u00ec h\u00f4m sau s\u1ebd c\u00f3 con l\u00f4 3 c\u00e0ng 373<\/span><\/p>\n V\u00e0o th\u1ee9 5 v\u00e0 th\u1ee9 7 con l\u00f4 97 hay ra<\/span><\/p>\n V\u00e0o th\u1ee9 7, ch\u1ee7 nh\u1eadt, th\u1ee9 2, th\u1ee9 3 con l\u00f4 33 hay ra<\/span><\/p>\n V\u00e0o th\u1ee9 4, th\u1ee9 5, th\u1ee9 6 con l\u00f4 66 hay ra<\/span><\/p>\n H\u00f4m tr\u01b0\u1edbc c\u00f3 con l\u00f4 18 th\u00ec h\u00f4m sau s\u1ebd v\u1ec1 con l\u00f4 97, 99 ho\u1eb7c ng\u01b0\u1ee3c l\u1ea1i<\/span><\/p>\n H\u00f4m tr\u01b0\u1edbc c\u00f3 con l\u00f4 45 th\u00ec h\u00f4m sau s\u1ebd v\u1ec1 l\u00f4 595 ho\u1eb7c 09<\/span><\/p>\n Con l\u00f4 58 xu\u1ea5t hi\u1ec7n th\u00ec 3 ng\u00e0y sau s\u1ebd c\u00f3 con l\u00f4 63<\/span><\/p>\n H\u00f4m tr\u01b0\u1edbc ra l\u00f4 68 th\u00ec h\u00f4m sau s\u1ebd c\u00f3 con l\u00f4 86<\/span><\/p>\n H\u00f4m tr\u01b0\u1edbc \u0111\u1ec1 v\u1ec1 05 th\u00ec h\u00f4m sau s\u1ebd c\u00f3 con l\u00f4 95<\/span><\/p>\n H\u00f4m tr\u01b0\u1edbc \u0111\u1ec1 v\u1ec1 29 th\u00ec h\u00f4m sau s\u1ebd c\u00f3 con l\u00f4 22 v\u00e0 ng\u01b0\u1ee3c l\u1ea1i<\/span><\/p>\n H\u00f4m tr\u01b0\u1edbc \u0111\u1ec1 v\u1ec1 k\u00e9p 00, 11, 22\u2026.99 th\u00ec h\u00f4m sau s\u1ebd c\u00f3 1 trong nh\u1eefng con l\u00f4 sau\u00a0: 010, 151, 060, 565. V\u00e0 sau \u0111\u00f3 1 tu\u1ea7n s\u1ebd v\u1ec1 nh\u1eefng con l\u00f4 232, 282, 373, 787.<\/span><\/p>\nL\u00f4 xi\u00ean l\u00e0 g\u00ec?<\/strong><\/span><\/h4>\n
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L\u00f4 xi\u00ean 2 s\u1ed1<\/strong><\/span><\/span><\/h2>\n
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L\u00f4 xi\u00ean 3 s\u1ed1<\/strong><\/span><\/span><\/h2>\n
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L\u00f4 xi\u00ean 4 s\u1ed1<\/strong><\/span><\/span><\/h2>\n
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B\u00ed k\u00edp \u0111\u00e1nh l\u00f4 xi\u00ean lu\u00f4n th\u1eafng<\/strong><\/span><\/span><\/h2>\n
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Quy lu\u1eadt con s\u1ed1 l\u00f4 hay ra nh\u01b0 sau<\/span><\/h4>\n
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